Hi everyone.
Recently CSN has approached me to announce a giveaway for $55.Only residents of USA and Canada are eligible for this $55 giveaway.CSN has more than 200 + online stores that cater to many of our needs.You can buy anything from a pair of trendy heels or a stylish bar stool for your kitchen, you can also find dinnerware sets for your kitchen or bedding sets for your bedroom or toys for your kids .You name it, they have it.So don't miss this wonderful giveaway.
To win this GiveAway there only 3things to do...
1) You must be a follower of the blog either by Google connect or Facebook and must subscribe to the feeds.
2) Let me know what you like or dislike about my blog "FoodLovers"
3) You must promote this GiveAway in your blog.
If you satisfy all the above conditions , leave a comment to me in this post and you get the chance to enter the Giveaway.
This GiveAway is ends by October 31st2010
http://meeyeehere.blogspot.com/2010/10/here-is-55-csn.html
I blogged ya! I am follower number 50!
Also,I looked around your blog and I like what I see.I need more pictures because I am a snoopy person and pictures help me to know the blog better.
Thanks for the chance and have a fabulous week
jacksoncrisman@yahoo.com
Nice givaways. I am already your follower, I like the way you put your recipes.
Beautiful give away..
I follow on gfc.
I love your recipes -- they inspire me to try new things.
I am following with google friends.
hillaryanna at yahoo.com
I'm a GFC follower and I subscribe via rss to google reader.
fourkidsrgreat(at)gmail.com
I love the recipes and the spices used.
fourkidsrgreat(at)gmail.com
I follow, I added you to my RSS reader, and I blogged here:
http://quiltznhoez.blogspot.com/2010/10/food-lovers-announcing-of-55-csn-stores.html
I like the simple, easy to read layout of your blog and the tasty Indian food recipes!
eemoody77 at gmail dot com
GFC follower, I'm new to your blog but love the recipes that I see. I added your info and link to my left sidebar http://tiffspixiedust.blogspot.com
....Tiffypoot @ (aol.com)